Question

When container of volume V is heated from normal temperature T1 K to T2 K ,the volume of expelled air at temperature T1 K is ∆V' .therefor value ∆V/V is

Answer 1

Given

Initial temperature =T1 k

Final temperature = T2 k

Initial volume V1 =v

Change in volume V2 = dv

(Don't have dal option in keyboard so using (d) for that)

Using Charles law

V directly proportional to T

V/T = contt.

So we can write

V1/T1 = V2/T2

V2/v1=T2/T1

V2/v1= dv/v

dv/v =T2/T1

If we take final volume as

Initial volume + expelled volume of air

V2= v+dv

Then

v+dv/v = T2/T1

1+(dv/v)=T2/T1

dv/v=T2/T1 - 1

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