when copper is bombarded with high-energy electrons,X-rays are emitted.calculate the energy(in joules)associated with the photons if the wavelength of X-rays is 0.154nm
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The energy associated with the photons of X rays with a wavelength of 0.154 nm is 1.29 × 10⁻¹⁵ J.
When copper is bombarded with high-energy electrons, X rays, with a wavelength of 0.154 nm (λ) are emitted.
We can calculate the energy (E) associated with the photons of these X rays using the Planck-Einstein relation.
E = \frac{h \times c }{\lambda } = \frac{(6.63 \times 10^{-34}J.s ) \times (3.00 \times 10^{8}m/s ) }{0.154 \times 10^{-9} m } ]= 1.29 \times 10^{-15} JE=
λ
h×c
=
0.154×10
−9
m
(6.63×10
−34
J.s)×(3.00×10
8
m/s)
]=1.29×10
−15
J
where,
h: Planck's constant
c: speed of light
The energy associated with the photons of X rays with a wavelength of 0.154 nm is 1.29 × 10⁻¹⁵ J.
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