Chemistry, asked by jbajaj421, 11 months ago

When copper wire is left in silver nitrate solution for sometime it was observed that solution turned blast green explain the observation write the balanced chemical equation to represent the change taking place

Answers

Answered by Hemu1432
3

Answer:

HEY MATE HERE IS YOUR ANSWER

A. COPPER IS MORE REACTIVE THAN SILVER. HENCE WHEN COPPER WIRE IS DIPPED IN SILVER NITRATE ( AgNO3 ) SOLUTION FORMING COPPER NITRATE WHICH IS BLUISH GREEN IN COLOUR.

B. Cu(S) + 2 AgNO3 (aq)....>Cu ( NO3 ) 2 (aq) + 2Ag (s)

THIS IS A DISPLACEMENT REACTION. A SHINING GREY WHITE DEPOSIT IF SILVER IS FORMED ON THE COPPER STRIP AND THE SOLUTION BECOMES BLUISH GREEN DUE TO THE FORMATION OF COPPER NITRATE.

HOPE IT HELPS

MARK AS BRAINLIEST..

Answered by marishthangaraj
0

The copper displaces the silver as copper metal is more reactive than silver.

  • According to the reactivity series of metals, copper is more reactive than silver metal.
  • When keeping the copper wire in a solution of silver nitrate, the copper ions go into the solution and the silver gets deposited onto the copper.
  • What happed is a displacement of the metal ions and is known as displacement reaction.
  • That's why we see a colour change in the solution as copper nitrate is a bluish-green solution.

2AgNO_{3} +Cu Cu(NO_{3})_{2}+2Ag

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