Question

When Cp=20 j/kg and 1mole of gas is present than CV is? (A) 3.36 J/kg k (B) 4.36 j/kg k (c) 5.36 j/kg k (d) 2.36 j/kg k


please give write answer with reason ​

Answer 1

Given : $\[{C_p}\]$  = 20 J Kg⁻¹ K⁻¹

              n = 1 mole

To Find : Value of $\[{C_V}\]$.

Solution :  

Formula used to find  $\[{C_V}\]$ is as follows-

         $\[{C_P} = {C_V} - nR\]$

Here,

         $\[{C_p}\]$ = heat capacity at constant pressure

        $\[{C_V}\]$ = heat capacity at constant volume

           n = number of moles

           R = gas constant

From following

        $\[{C_p}\]$  = 20 J Kg⁻¹ K⁻¹

         n  = 1 mole

         R = 8.314 J mole⁻¹ K⁻¹

putting all the values, we get

  $\[{C_P} = {C_V} - nR\]$

     $\[{C_V}\]$  = 20 - 1×8.314

     $\[{C_V}\]$ = 5.36 J Kg⁻¹ K⁻¹

Therefore, value of  $\[{C_V}\]$  is found to be 5.36J Kg⁻¹ K⁻¹.

Hence, Value of  $\[{C_V}\]$ is  5.36J Kg⁻¹ K⁻¹.