Question

when cp=20J/kg k and 1mole of gas is present then cv is ?
a:2.36J/kg k
b:3.36J/kg k
c:4.36J/kg k
d:5.36J/kg k​

Answer 1

Given:

Cp = 20 J Kg⁻¹ K⁻¹

n = 1 mole

To find:

Heat capacity at constant volume, Cv

Solution:

Formula used to find Cv is as follows-

    Cp - Cv = nR

here, Cp = heat capacity at constant pressure

         Cv = heat capacity at constant volume

         n = number of moles

         R = gas constant

given, Cp = 20 J Kg⁻¹ K⁻¹

          n = 1 mole

           R = 8.314 J mole⁻¹ K⁻¹

putting all the values, we get

     Cv = Cp - nR

            = 20 - 1×8.314

            = 5.36 J Kg⁻¹ K⁻¹

Therefore, value of Cv is found to be 5.36J Kg⁻¹ K⁻¹.

So, Option(d) is correct.

Answer 2

Answer:

4.36J/kgk

Explanation:

good. answer