Question

When crossing was carried out between a plant whose genotype is BB with another one whose genotype is bb ,150 individuals were produced so ,the number of the produced individuals whose genotype is Bb is .. . Individuals

Answer 1

$\huge{ \pink{\mathfrak{{Question:−}}}}$

When crossing was carried out between a plant whose genotype is BB with another one whose genotype is bb ,150 individuals were produced so ,the number of the produced individuals whose genotype is Bb is .. . Individuals.

$\huge{ \pink{\mathfrak{{Answer:−}}}}$

⇒ An organism with two dominant alleles for a trait is said to have a homozygous dominant genotype. Using the eye color example, this genotype is written BB. An organism with one dominant allele and one recessive allele is said to have a heterozygous genotype

⇒ AaBbCC will produce 4 types of gametes which are as follows- ABC, AbC, aBC, abC. The number of gametes formed is decided by the number of heterozygous alleles present in the given genotype. 2^n is the formula used to find it out, where n=number of heterozygous alleles present in the genotype. Say for example, in the above genotype Aa & Bb are the 2 heterozygous alleles, so here n=2. Putting the values in the formula , we get 2^2=4. Hence 4 types of gametes are formed.

So the correct option is 'four'.

$\huge{ \red{\mathfrak{{Conclusion:−}}}}$

⇒ the number of the produced individuals whose genotype is Bb is Individuals.