when Cu +2 ion is treated with KI, a white precipitate is formed.Explain the reaction with a help of chemical equation
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Answered by
27
Hi friend,
The reaction is:-
2Cu2+ + 5KI⟶ 2CuI + KI3
On treatment of Cu 2+ ion with Ki, a white salt (CuI) in a brown solution (KI3) is formed.
Hope it helps!
The reaction is:-
2Cu2+ + 5KI⟶ 2CuI + KI3
On treatment of Cu 2+ ion with Ki, a white salt (CuI) in a brown solution (KI3) is formed.
Hope it helps!
Answered by
6
See the attachment for the reaction
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