Question

when Cu2S is converted into Cu2+ and SO2- then equivalent weight of Cu2S will be (M= mol wt of Cu2S)

A=M,B=M/2,C=M/4,D=M/8

Answer 1

N2H4 can be oxidised to N2 by 24 ... A 10 gm mixture of Cu2S and CuS was treated .... (B) (mol.wt.)/2. (C) (mol.wt.)/3. (D) ( mol.wt.)/4. Sol. 5. 20 ml of 0.1 M ...

Answer 2

Answer:

The equivalent weight of Cu₂S will be equal to M/8.

Explanation:

According to the given chemical equation:

                        $Cu_{2}S+O_{2}$  →  $2Cu+SO_{2}$

Oxid" state:   +1   -2     0        +2    +4  -2

Net change in Oxidation state: for Cu = 2 and for S (from -2 to+4) = 6

Therefore n-factor $=2+6=8$

Equivalent weight = molecular weight/n-factor

Given that  M= molecular weight of Cu₂S

The equivalent weight of Cu₂S   $=\frac{M}{8}$