Question

When current in a coil changes from 5a to 2a in 0.1 s an average voltage of 50v is produced. The self inducatance of teh coil is

Answer 1

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Answer 2

The self inductance of the coil is 1.67 H.

Explanation:

It is given that,

Initial current, I = 5 A

Final current, I' = 2 A

Time in changing current, t = 0.1 s

Voltage of the coil, V = 50 V

To find,

The self inductance of the coil.

Solution,

Due to the change in current with time and emf is induced in the coil. It is given by in terms of self inductance as :

$\epsilon=L\dfrac{dI}{dt}$

$L=\dfrac{\epsilon}{(dI/dt)}$

$L=\dfrac{50\ V}{(5-2/0.1)}$

$L=1.67\ H$

So, the self inductance of the coil is 1.67 H.

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Self inductance

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