Question

When current in a coil changes from 6 A to 2 A in 0.1 s, and value of induced e.m.f is 40 V . The self-inductance of the coil is *​

Answer 1

Answer:

self inductance = change in current/time

Explanation:

6-4/0.1 = 4/0.1 = 40 V

e = 40

change in current/time = 40

self inductance = 40/40 = 1H

if I have  done any mistake please forgive me