Question

When α-D-glucose and β-D-glucose are dissolved in water
in two separate beakers I and II respectively and allowed to
stand, then –
(a) specific rotation in beaker I will decrease while in II will
increase upto a constant value
(b) the specific rotation of equilibrium mixture in two
beakers will be different
(c) the equilibrium mixture in both beakers will be
leavorotatory
(d) the equilibrium mixture in both beakers will contain only
cyclic form of glucose

Answer 1

$\huge\bold\red{Answer:-}$

(d) the equilibrium mixture in both beakers will contain only cyclic form of glucose

Answer 2

When α-D-glucose and β-D-glucose are dissolved in water  in two separate beakers I and II respectively and allowed to  stand, then –specific rotation in beaker I will decrease while in II will  increase upto a constant value

Step by step explanation:

When α-D-glucose and β-D-glucose are dissolved in water  in two separate beakers I and II respectively and allowed to  stand then the following equilibrium reaction is occurred.

$\alpha -D-Glucose \Leftrightarrow chain\,form \Leftrightarrow\beta -D-Glucose$

The Specific rotation value of α-Glucose is +111

The Specific rotation value of β-Glucose is +19.

The specific rotation value of α-Glucose values is standard and the Specific rotation value of β-Glucose isincreases still it gets +52.5.

The phenomenon is known as mutarotation.

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