Question

when divided by X-2, find the value of a.
If the polynomials x' + ax? +5 and x2 - 2x + a are divided by (x+2) leave the same
remainder, find the value of a.​

Answer 1

Answer:

$x - 2 = 0$

$x = 2$

$p(x) = x + ax + 5$

$p(2) = 2 + 2a + 5$

$2a + 7$

now,

$x + 2 = 0$

$x = - 2$

$p(x) = {x}^{2} - 2x + a$

$4 + 4 + a$

$a + 8$

both leaves the remainder same,

$2a + 7 = a + 8$

$2a - a = 8 - 7$

$a = 1$