When dividing x^3+nx^2+4nx-6 by x+3 the remainder is -48. What is the value of n?
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Answered by
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let x+3 = 0
x = -3
now put the value in f(x)
according to questions
f(-3) = -48
(-3)³ + n(-3)² + 4(-3)n - 6 = -48
-27 + 9n - 12n - 6 = -48
-33 - 3n = - 48
3n = 48 - 33
3n = 15
n = 5
Hope it may help you
x = -3
now put the value in f(x)
according to questions
f(-3) = -48
(-3)³ + n(-3)² + 4(-3)n - 6 = -48
-27 + 9n - 12n - 6 = -48
-33 - 3n = - 48
3n = 48 - 33
3n = 15
n = 5
Hope it may help you
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