Question

When each side of a square is increased by 3m the area become 52 sq. M what is the length of side of the original square

Answer 1

Answer:

let the original side be X

then new side is (x-3)

and new area is 64 m^2= (X-3)^2

i.e. 64=x2 +9–6x

i.e. x2–6x-55=0

i.e. x2–11x +5x-55=0

i.e. x(x-11)+5(x-11)=0

i.e. (x-11)(x+5)=0

x= 11, -5

so the length can be negative so the answer will be 11.