When each side of a square was increased by four m the area became 256 square metres
A) write down a second degree equation by taking the side of original square as x
B) what was what was the length of a side of the original square
answer).
![(x + 4) {?}^{2} = 256 (x + 4) {?}^{2} = 256](https://tex.z-dn.net/?f=%28x+%2B+4%29+%7B%3F%7D%5E%7B2%7D+++%3D+256)
![x {?}^{2} + 4 = \sqrt{256} x {?}^{2} + 4 = \sqrt{256}](https://tex.z-dn.net/?f=x+%7B%3F%7D%5E%7B2%7D++%2B+4+%3D++%5Csqrt%7B256%7D+)
![x + 4 = 16 x + 4 = 16](https://tex.z-dn.net/?f=x+%2B+4+%3D+16)
![x = 16 - 4 = 12 x = 16 - 4 = 12](https://tex.z-dn.net/?f=x+%3D+16+-+4+%3D+12)
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Answer:
a=16
b=12
Step-by-step explanation:
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