when each term of sin²Θ + cos²Θ = 1 is divided by sin²Θ, what will be the result?
Answers
Answered by
8
Step-by-step explanation:
I hope this is helpful for you
Attachments:
Answered by
3
Answer:
cosec^2A - cot^2A =1
Step-by-step explanation:
sin^2A/ sin^2A +cos^2A/ sin^2A=1/ sin^2A
1+cot^2A=cosec^2A (cosecA=1/sinA and cotA =sinA / cosA)
1=cosec^2A-cot^2A
cosec^2A-cot^2A=1
Similar questions