Question

When electricity is passed through a solution of AIC13. 13.5g of Alis discharged. The amount of
charge passed is​

Answer 1

Answer:

1.5 Faraday or 144750 coulomb

Explanation:

Al(3+) + 3e(-) = Al

1 mol Al (27 g) is formed when 3F electricity is passed

So, 13.5 g Al production requires 1.5F electricity.

1.5F = (1.5)(96500 C) = 144750 C  

Answer 2

W/Eq.wt=Q/F

Eq wt=mol.wt/n Factor

N factor for AlCl3 is 3 as 3 electrons are exchanged between Al and Cl

Eq=27/3=9

W/Eq.wt=Q/F

13.5×F/9=Q.

Q=1.5F.

Q=144750 ( F=96500)

I hope this helps ( ╹▽╹ )