Question

When electricity is passed through a solution of AlCl3 13.5 g of Al is deposited. The number of faradays must

be

(1) 1.0 (2) 1.5 (3) 0.5 (4) 2

Answer 1

hey sisy !!!!!!

here is your required answer- (2)

the reaction at cathode is

Al ( 3+) + 3e---------->Al. (n=3)

→applying the equation

w = E×i×t/F

by substituting the values

♦ i × t =
13.5 /(27/3)×F

=13.5/9 ×F

=1.5 F

I hope this will help u ;)

♥dhathri123♥

Answer 2

Al 3+   + 3e   ---------->   Al

1 mole of Al ---- 27 

13.5  is given -- which is 0.5 mole 

1 Faraday = 1 mole of electrons

1 mole   ----------- 30 faraday
0.5  mole ---------- ?

0.5 x 30

= 1.5 faraday
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