when electromagnetic radiation of wavelength 300nm falls on the surface of sodium electrons are emitted with kinetic energy of 1.68 into10^-5joule move what is the minimum energy needed to remove on electron from sodium ? what is the maximum wavelength that will cause a photoelectron to be emitted
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Answer:
Explanation:
We have to find hν
o
hν
o
=hν−KE
=
λ
h.C
−
6.023×10
23
1.68×10
5
5/mol
hν
o
=
300×10
−9
m
6.626×10
−34
×3×10
8
−
6.023×10
23
1.68×10
5
=0.06626×10
−17
−0.2789×10
−18
=0.06626×10
−17
−0.02789×10
−17
hν
o
=0.03837×10
−17
J
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