Question

When Electromagnetic Radiation Wave Length Free 10 Nanometer Follows Late Of Korea Electron Images With Kinetic Energy 1.5 Electron Volts Determined The Book Solution Of Sodium​

Answer 1

Answer:

The energy of the photon, 

E=λhc

=150×10−126.626×10−34×3×108

=1.325×10−15J. 

The energy of the ejected electron is 

21mv2=21×9.11×10−31×(1.5×107)2=1.025×10−16. 

The energy with which the electron was bound to the nucleus is: 

Energy of photon − Energy ejected by electron =13.25×10−16−1.025×10−16=12.225×10−16J

                                                                                   =7.63×103eV.

Answer 2

Answer:

The energy of the photon, 

E=λhc

=150×10−126.626×10−34×3×108

=1.325×10−15J. 

The energy of the ejected electron is 

21mv2=21×9.11×10−31×(1.5×107)2=1.025×10−16. 

The energy with which the electron was bound to the nucleus is: 

Energy of photon − Energy ejected by electron =13.25×10−16−1.025×10−16=12.225×10−16J

                                                                                   =7.63×103eV.