Question

When electronic transition takes place from 2
nd orbit to 1

st

orbit in a mono electronic species the

wavelength of emission found to be is 3.04 × 10 race to power -8 meter then what is the atomic number of mono

electronic species​

Answer 1

Answer:

Explanation:

1/λ=RZ²(1/1²-1/2²)

1/λ=RZ²(1/1-1/4)

1/λ=(3/4)Z²R

λ=(4/3)RZ²

Here R=10.96×10^6 /m

3.04×10^(-8)=(4/3)(10.96×10^6)(Z²)

Z²=(3×3.04×10^-8)/(4×10.96×10^6)

Z²=2.080×10^-15

Z=4.56×10^-8

Z=4.56

Z=5(approximately)