when electrons are added in the 6s orbital, what happens to the energy level of the 5d orbitals? As a result after the electron enters 5d orbital in the lanthanum, in which orbital does the next electron enter in cerium ?
Answers
The Lanthanum is a D-transition metal (group 3), i.e. its valence electron (outermost electron) in D-orbital.
There are 5 different D-orbitals and hence, due to the total duration of the total (10 electrons) filling a total of these elements, these elements of D-transition metals are produced.
In periodic table the first element after Lanthanum (LA) is Cerium (CE).
The Cerium is the first element in which a 4F-orbital is filled with an electron, so the c is starting to block the elements of the so-called F-transition metals.
In some cases (C, GD, and Lu) electrons are in D-orbitals because in the electron configuration of 4-F-transition elements, the energy is very similar between 4F and 5D orbitals.
Keeping all the different contributions in the filled orbital is the least possible energy i. e. electrostatic interaction, angular and spin moment, etc.
The Lanthanum is a D-transition metal (group 3), i.e. its valence electron (outermost electron) in D-orbital.
There are 5 different D-orbitals and hence, due to the total duration of the total (10 electrons) filling a total of these elements, these elements of D-transition metals are produced.
In periodic table the first element after Lanthanum (LA) is Cerium (CE).
The Cerium is the first element in which a 4F-orbital is filled with an electron, so the c is starting to block the elements of the so-called F-transition metals.
In some cases (C, GD, and Lu) electrons are in D-orbitals because in the electron configuration of 4-F-transition elements, the energy is very similar between 4F and 5D orbitals.
Keeping all the different contributions in the filled orbital is the least possible energy i. e. electrostatic interaction, angular and spin moment, etc.