Chemistry, asked by ayesharaja719, 1 month ago

When enzyme solutions are heated, there is a progressive loss of catalytic activity over time due to denaturation of the enzyme. A solution of the enzyme hexokinase

incubated at 45 C lost 50% of its activity in 12 min, but when

incubated at 45 C in the presence of a very large concentration of one of its substrates, it lost only 3% of its activity

in 12 min. Suggest why thermal denaturation of hexokinase

was retarded in the presence of one of its substrates​

Answers

Answered by awesomeshivans75
0

Answer:

https://www.chegg.com › enzyme-s...

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When enzyme solutions are heated, there is a progressive loss of ...

Answered by KajalBarad
0

Hexokinase is a phosphorylating enzyme that converts six-carbon sugars to hexose phosphate. In most cases, glucose is one of the most important substrates of hexokinase. This enzyme is relatively stable at temperatures below 40 degrees Celsius but loses activity at temperatures above this level. This enzyme's loss percentage can be reduced in the presence of its substrate, glucose. Denaturation reduces the efficiency of enzymes. Hexokinase forms an enzyme-substrate complex in the presence of glucose because glucose binds to the active site of the substrate. This formation slows the unfolding of the protein and increases the stability of the enzyme hexokinase; thus, denaturation is slowed.

As a result, in the presence of its substrate, hexokinase's thermal denaturation can be delayed.

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