Question

When equal weights of methyl alcohol and
ethyl alcohol react with excess of sodium
metal, the volume of H, liberated is more in
the case of​

Answer 1

Answer:

2C2H5OH + 2Na ⟶ 2C2H5ONa + H2 2CH3OH + 2Na ⟶ 2CH3ONa + H2 Thus 2 mole of Ethanol give 1 mole of H2 or 2 mole of Methanol give 1 mole of H2 If CH3OH