When ethanoic acid reacts with sodium hydrogen carbonate, the salt ‘X’ is
formed and gas ‘Y’ is evolved.
(a) Identify ‘X’ and ‘Y’.
(b) Write balanced chemical equation of above reaction.
(c) Describe a test to identify the gas ‘Y’ evolved.
Answers
Answered by
31
X = ch3cooNa
Y= CO2
pass CO2 gas through lome water so ot turn lime water milky
Y= CO2
pass CO2 gas through lome water so ot turn lime water milky
Answered by
94
When ethanoic acid reacts with sodium hydrogen carbonate, the salt ‘X’ is
formed and gas ‘Y’ is evolved.
A]
X---- SODIUM ETHANOATE. [CH3COONa]
Y----- CO2
B]
CH3COOH +NaHCO3 --------->CH3COONa+CO2+H2O
C]CO2 GAS can be tested by passing into lime water, which turns into milky white.
formed and gas ‘Y’ is evolved.
A]
X---- SODIUM ETHANOATE. [CH3COONa]
Y----- CO2
B]
CH3COOH +NaHCO3 --------->CH3COONa+CO2+H2O
C]CO2 GAS can be tested by passing into lime water, which turns into milky white.
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