Chemistry, asked by deepak9140, 1 day ago

When ethanoic acid reacts with sodium hydrogencarbonate, then a salt X is formed and a gas Y is evolved. Name the salt X and gas Y. Describe an activity with the help of a labelled diagram of the apparatus used to prove that the evolved gas is the one which you have named. Also write the chemical equation of the reaction involved.

Answers

Answered by sanap111006

Explanation:

Explanation:When ethanoic acid reacts with sodium hydrogen carbonate, a brisk effervescence of carbon dioxide gas is evolved. The salt formed as a result of this reaction is sodium ethanoate.

Explanation:When ethanoic acid reacts with sodium hydrogen carbonate, a brisk effervescence of carbon dioxide gas is evolved. The salt formed as a result of this reaction is sodium ethanoate.Let's react ethanoic acid with sodium hydrogen carbonate.(1) Take a boiling tube and add 0.5gm of sodium hydrogen carbonate to it. To this, add 2 ml of dilute ethanoic acid through a thistle funnel.

Answered by itzmedipayan2

Answer:

Ethanoic acid reacta with sodium hydrogencarbonate forms a salt sodium ethoanate and water along with liberation of carbon dioxide gas with a brick effervescence. So the salt X is sodium ethanoate.

Chemical formula:-

$CH_{3}COON_{a}$

The name of the gas Y is carbon dioxide. (CO_2)

Now,

${\huge{\underline{\small{\mathbb{\pink{REFER \ TO \ THE \ ATTACHMENT}}}}}}$

The experiment can be carried out by using an apparatus shown in the attachment:

(i) Approximately 0.5g of sodium hydrogencarbonate can be taken in a test tube.

(ii) Dilute ethanoic acid around 2 ml should be added to the test tube through a funnel.

(iii) A brisk effervescence will be observed due to release of carbon dioxide gas.

(iv) The gas will be passed into a test tube containing lime water.

(v) The lime water present in the test tube will be turned milky.

(vi) Since carbon dioxide turns lime water to milky, we can conclude that the liberated gas is carbon dioxide.

(vii) Thus the release of carbon dioxide through brisk effervescence during the reaction between ethanoic acid and hydrogencarbonate is confirmed by the experiment.

The chemical equation of the reaction is :-

$CH_{3}COOH + N_{a}HCO_{3} \to \\ \\ CH_{ 3}COON _{a} + CO_{2} + H_{2}O$

Hope it helps you from my side

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When ethanoic acid reacts with sodium hydrogencarbonate, then a salt X is formed and a gas Y is evolved. Name the salt X...

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