when ethanol is heating in presence of concentrated sulphuric acid at temp of 443k
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Δ443K
CH₃CH₂OH---------------------->CH₂=CH₂+H₂O
H₂SO₄
i HOPE It MaY Be HeLpFuLl for u
CH₃CH₂OH---------------------->CH₂=CH₂+H₂O
H₂SO₄
i HOPE It MaY Be HeLpFuLl for u
dnsharma74:
thanks for mark as brainliest answer
Answered by
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Hello!
Here is your answer!
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As H2SO4 or Sulpuric acid is a strong dehydrating agent ethanol gets dehydrated and forms ethene gas.
Sulphuric acid acts only as a catalyst.
Catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process.
The water or H2O produced from the reaction gets mixed with sulphuric acid (H2SO4) and it gets diluted.
Equation: C2H5OH ----------------------------------------------------- > C2H4 + H2O
excess of H2SO4 & high temperature 443K
==========================================================
Hope it helps!
Here is your answer!
==========================================================
As H2SO4 or Sulpuric acid is a strong dehydrating agent ethanol gets dehydrated and forms ethene gas.
Sulphuric acid acts only as a catalyst.
Catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process.
The water or H2O produced from the reaction gets mixed with sulphuric acid (H2SO4) and it gets diluted.
Equation: C2H5OH ----------------------------------------------------- > C2H4 + H2O
excess of H2SO4 & high temperature 443K
==========================================================
Hope it helps!
You are a nerd unlike me!! :p
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