Question

when ethanol is treated with red phosphorus in presence of iodine the following alkyl halide is formed​

Answer 1

Ethyl Iodide

Explanation:

• Red phosphorus in iodine forms $PI_{3}$ as the following reaction takes place

        $2P + 3I_{2}$ → $2PI_{3}$

• And when that  $PI_{3}$ reacts with ethanol, it forms ethyl iodide and $H_{3}PO_{3}$ by the following reaction,

       $CH_{3} - CH_{2}-OH +PI_{3}$ → $CH_{3} - CH_{2}-I + H_{3}PO_{3}$

• It is a type of nucleophilic substitution reaction that is one nucleophile replaces the other.

Thus, the resulting alky halide is ' Ethyl Iodide.'