Chemistry, asked by hr553689, 6 months ago

When ethanol is warmed with ethanoic acid in the presence of strong acid catalyst, an ester
ethyl ethanoate is formed.
CH3CH2OH + CH3CO2H
During this reaction:
A) Alcohol is reduced
B) O-H bond in ethanoic acid is broken
CH3CO2CH2CH3
C) 0-H bond in ethanol is broken
D) Acid is oxidized​

Answers

Answered by Anonymous
7

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Ethanoic acid reacts with ethanol in the presence of concentrated sulphuric acid as a catalyst to produce the ester, ethyl ethanoate. The reaction is slow and reversible. To reduce the chances of the reverse reaction happening, the ester is distilled off as soon as it is formed.

Answered by ghulamqadirtareenhar
0

Answer:

B

Explanation:

the concept hidden in it is acidic strength

the one which is more acidic will lose its hydrogen.

O---H bond of ethanoic acid is broken in order to form ester and h2o molecule . OH come in water from alchole

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