When ethyl alcohol and acetic acid mixed together in equimolecular proportions, equilibrium is attained when twothird of the acid and alcohol are consumed. the equilibrium constant of the reaction will be choose one:?
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Answer:
C2H5OH +CH3COOH =CH3COOC2H5 +H2O
Concentration before equillibrium:
C2H5OH=C
CH3COOH=C
CH3COOC2H6=H2O=0
Concentration after equilibrium :
C2H5OH=CH3COOH=C-(2/(3*C))
CH3COOC2H5=H2O=(2/(3*C))
K=((2/(3*C))^2) / ((C-(2/(3*C)))^2)
K=4
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