When ethyne ( HC = CH ) is passed through dilute sulphuric acid in
presence of mercuric sulphate at 333K, the product formed is
(1) CH3-C-CH2
(2) CH3 -C-H
(3)
CH --CH2-CH,
(4)
none of these
Answers
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Answer:
The correct answer is option D. None of the above.
Whenever the ethyne is passed through sulphuric acid, it will first break the triple bond.
The triple bond is broken down by the presence of water which is H₂O.
This further gives a compound that is simpler and has double bonds.
The intermediate compound will then react with sulphuric acid.
We write sulphuric acid as H₂SO₄.
This will be done in the presence of a catalyst which will be used to react with sulphur leaving the oxygen atom attached to the intermediate compound.
The final product that we will get will be CH₃C=0CH₂.
Since the oxygen will react with the ethyne, thus we might find an oxygen atom attached to the final compound. Here, neither option has an oxygen atom attached.
Therefore, our correct answer will be option D.
To know more about compounds, refer: https://brainly.in/question/13953256
To know more about carbon, refer: https://brainly.in/question/457186
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