When excess carbon (IV) oxide is passed into lime water in a test tube, the product formed is (A) Ca(OH) 2 (B) CaCO3 (C) Ca(HCO3)2 (D) CaO
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Answer:
The answer is CaCO3
Explanation:
Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O
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