Question

when F=x and c=x than the value of x in c/5=F-32/9​

Answer 1

Answer:

$c \div 5 = (f - 32) \div 9 \\ x \div 5 = (x - 32) \div 9 \\ 9x = 5x - 160 \\ 4x = 160 \\ x = 160 \div 4 \\ x = 40 \: degree$

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