when f(x)=x^100 is divided by (x^2)-3x+2.then the remainder is
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The answer is (2^100-1)x+(1-2^100)/2
Explanation: x^2-3x+2=(x-1)(x-2).
As the divisor is a quadratic equation, remainder power = 1=ax+b.
remainder when x=1,
a+b=1^100
remainder when x=2,
2a+b=2^100.
On solving, the a=2^100-1,b=(1-2^100)/2
then substitute in ax+b, u will get the answer
Explanation: x^2-3x+2=(x-1)(x-2).
As the divisor is a quadratic equation, remainder power = 1=ax+b.
remainder when x=1,
a+b=1^100
remainder when x=2,
2a+b=2^100.
On solving, the a=2^100-1,b=(1-2^100)/2
then substitute in ax+b, u will get the answer
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