When f(x) = x3 + ax2 + bx + 2 is divided by (x – 1), it leaves a remainder of 5 and when divided by (x + 1) the remainder is 13. Using remainder theorem, find the values of a and b in f(x).
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Step-by-step explanation:
f(x)=x³+ax²+bx++2
f(1)=5 , f(-1)=13
1+a+b+2=5
a+b=2 equation 1
f(-1)=13
-1+a-b+2=13
a-b=12 equation 2
solving equation 1 and 2
a=7 b= -5
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that is a correct answer
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