Question

when ferrous sulphate acts as reductant
its equivalent werght is
1) twice that of its molécular weight
2) equal to its molecular weight
3) one-half of its molecular weight
4) One-third of its molecular weight​

Answer 1

Answer: 2) Equal to its Molecular Weight

Explanation:

FeSO₄, when acts as a reducing agent, it oxidises and reduces the reactant.

The oxidation number if Iron in Ferrous Sulphate is +2 (Fe⁺²). When it oxidises, it loses 1 electron and converts into Fe⁺³.

$Eq. Mass = \frac{Molecular Mass}{Valency Factor}$

In the reaction when Iron changes from +2 to +3, there is change of 1 electron. Therefore, Valency Factor is 1

$Eq. Mass = \frac{152}{1}$

Hence, Equivalent Mass = 152 = Molecular Weight

Hope it Helps!