Math, asked by Pakali730, 5 months ago

When finding the square root of 49 using repeated subtraction of odd numbers starting from 1, it takes 'n' steps to get 0. What is the value of 'n'?
1️⃣ 6
2️⃣ 8
3️⃣ 5
4️⃣ 7

Answers

Answered by monisha00211
0
4) 7 ..is the answer
Answered by RvChaudharY50
1

Question :- When finding the square root of 49 using repeated subtraction of odd numbers starting from 1, it takes 'n' steps to get 0. What is the value of 'n'?

A) 6

B) 8

C) 5

D) 7.

Solution :-

we know that,

  • If natural number is a square number, then it has to be the sum of successive odd numbers starting from 1.
  • Odd numbers are which do not divide by 2.

So,

Square root of 49 using repeated subtraction of odd numbers starting from 1 :-

  1. 49 - 1 = 48
  2. 48 - 3 = 45
  3. 45 - 5 = 40
  4. 40 - 7 = 33
  5. 33 - 9 = 24
  6. 24 - 11 = 13
  7. 13 - 13 = 0 .

Here, we got the result 0 in the 7th step, so we can say that, √49 = 7.

Hence, value of n is 7 steps. (Option D).

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