when force F making angle 60 with displacement d then work on body will be?
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Answer:
F is making an angle 60 °
therefore horizontal force = Fcos 60°
" " Vertical " = Fsin 60°
Work done = Force × Displacement
=> Horizontal Work= Fd (3^1/2)/2
=> vertical work = 0
therefore total work done = Fd(1.732)/2
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