Question

When forces F1 , F2 and F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular ,then the particle remains stationary . If the force F1 is now removed then the acceleration of the particle is---

Answer 1

The particle remains stationary on the application of three forces that means the resultant force is 0.

This implies

F1 = - (F2 + F3)

Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.

Therefore, the acceleration of the particle is F1/m

Hope it helps u.

Answer 2

Answer:

$a =F1/ m$

Explanation:

3. since the particle remains stationary, the resultant of F⃗ 1,F⃗ 2 and F⃗ 3 is zero, i.e.

$F 1+F2+F3=0\\F1=-(F2+F3)$F⃗ 1=−(F⃗ 2+F⃗ 3)

Thus magnitude of F1 is equal to the magnitude of (F2+F3) but opposite in direction. Hence if F1 is removed, the magnitude of the force on the particle = magnitude of (F2+F3)=− magnitude of F1 ∴ Acceleration $a =-F1/ m$Magnitude of acceleration $a =F1/ m$

but its direction is opposite to F1.