When four coins are tossed simultaneously, in what number of the outcomes at most two of the coins will turn up as heads
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Answer:
P.O = T , H
4 coins outcomes are
= (T,T,T,T) (H,H,H,H) (T,H,H,H) (H,T,H,H) (H,H,T,H) (H,H,H,T) (H,T,T,T) (T,H,T,T) (T,T,H,T) (T,T,T,H) (H,H,T,T)
(T,T,H,H) (T,H,H,T) (H,T,T,H) = 14
T.O = 8
PROBABILITY OF GETTING at most two of the coins will turn up as heads = 8/14 = 4/7
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