Question

when four consecutive integers are added the sum is 46 find the integers....
.. hi goodevening suman​

Answer 1

Explanation:

Let the first integer be x, then the next three consecutive integers will be,

(x+1),(x+2) and (x+3)

According to the problem,

x+(x+1)+(x+2)+(x+3)=46

x+x+1+x+2+x+3=46

On further calculation , we get,

4x+6=46

4x=46−6

4x=40

x=

4

40

We get,

x=10

Therefore , four consecutive integers are 10,(10+1),(10+2) and (10+3) i.e., 10,11,12 and 13