Question

When four fair dice are rolled simultaneously, in how many outcomes will at least one of the dice show 3?

Answer 1

Answer:

P(3) = 91/216

Step-by-step explanation:

P(number) = ( 6^n - 5^n ) / 6^n

where,

n = no. of dice

When,

1. n = 1

P(3) = ( 6 - 5 ) / 6 = 1 / 6

2. n = 2

P(3) = ( 36 - 25 ) / 36 = 11 / 36

3. n = 3

P(3) = ( 216 - 125 ) / 216 = 91 / 216