Question

when gaseous HI is irradiated with light of wavelength 253 nm it is absorbed that 1.85×10-2 mole decompose when 4184 joules of radiation absorbed. calculate the quantum yield of the reaction​

Answer 1

Answer:

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Answer 2

Answer:

The quantum yield of the reaction, Ф, is 2.11.

Explanation:

Given,

The number of moles of gaseous HI decomposed = 1.85 × 10⁻² mol

The wavelength of the light, λ = 253nm

Convert nm into m

• 1 nm = 10⁻⁹ m
• 253 nm = 253 × 10⁻⁹ m

The energy of the radiation absorbed, E = 4184 J

The quantum yield of the reaction, Ф =?

As we know,

• The number of moles (n) of photons absorbed can be calculated by the equation given below:
• $n = \frac{E\lambda}{N_{A} hc}$

Here,

• n = The number of moles of photons absorbed
• E = The energy of the radiation absorbed = 4148 J
• λ = The wavelength of the light = 253 × 10⁻⁹ m
• $N_{A}$ = Avagadro number = 6.022× 10²³ mol⁻¹
• h = The Planck's constant = 6.626 × 10⁻³⁴ Js
• c = Speed of the light = 3 × 10⁸ m/s

After putting all the values in the equation, we get:

• $n = \frac{4148\times 253\times 10^{-9} }{6.022\times10^{23} \times 6.626\times 10^{-34} \times 3\times 10^{8} }$
• $n = \frac{1049444\times 10^{-9} }{119.7 \times 10^{-3} }$
• $n = 8767.28\times 10^{-6} }$ mol

Now,

The quantum yield can be calculated by the equation:

• $\phi = \frac{moles of HI decomposed}{moles of photons absorbed}$
• $\phi = \frac{1.85\times 10^{-2} }{8767.28\times 10^{-6} }$
• $\phi = 2.11$

Hence, the quantum yield, Ф = 2.11.