. When gaseous hydrochloric acid reacts with liquid ammonia, what is the product produced? . Combination reaction c. displacement reaction. Decomposition reaction d. double displacement
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i) 1 mole occupies 22.4L volume
∴ moles of NH
3
present=
22.4
67.2
=3
(ii) 1 mole of NH
3
reacts with 1 mole of HCl to give 1 mole of NH
4
Cl. Here only 1 mole of HCl & 3 moles of NH
3
are present. Hence, 1 mole of NH
4
Cl is produced.
Mass of NH
4
Cl produced= 1× Molecular mass
=1×(14+4×1+35.5)
=53.5g
(iii) Here NH
3
is present in excess than what is required to react with 1 mole HCl. Hence 3−1=2 moles of NH
3
will remain after completion of the reaction.
(iv) Chemical reaction involved is:
NH
3
+HCl⟶NH
4
Cl .
∴ moles of NH
3
present=
22.4
67.2
=3
(ii) 1 mole of NH
3
reacts with 1 mole of HCl to give 1 mole of NH
4
Cl. Here only 1 mole of HCl & 3 moles of NH
3
are present. Hence, 1 mole of NH
4
Cl is produced.
Mass of NH
4
Cl produced= 1× Molecular mass
=1×(14+4×1+35.5)
=53.5g
(iii) Here NH
3
is present in excess than what is required to react with 1 mole HCl. Hence 3−1=2 moles of NH
3
will remain after completion of the reaction.
(iv) Chemical reaction involved is:
NH
3
+HCl⟶NH
4
Cl .
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