Question

When gauss law is usef inside a spherical cavity within uniformly charged solid sphere then I get that


$∮E.dA=Q_{enclosed}/ϵ_0$



Which should imply that E=0

 since charge inside the cavity is 0.

But my book states electric field inside the cavity is not 0.

Where am I going wrong?
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Answer 1

Answer:

• The electric field of a sphere of uniform charge density and total charge charge Q can be obtained by applying Gauss' law. Considering a Gaussian surface in the form of a sphere at radius r > R, the electric field has the same magnitude at every point of the surface and is directed outward.

Explanation:

• please make it a brainliest answer.

Answer 2

Explanation:

Which should imply that E=0

since charge inside the cavity is 0.

But my book states electric field inside the cavity is not 0.

Where am I going wrong?