Question

when glass slab of refractive index is 3/2 is placed on a dot on a paper. the dot appears to be raised by 1 cm what is the thickness of the glass sab​

Answer 1

Explanation:

Thanks for A2A.

Shift=realdepth∗(1−1/r.i.)

Shift=10∗(1−1/1.5)

Shift=10∗[(1.5−1]/1.5)

Shift=10∗(0.5/1.5)

Shift=10∗(1/3)

Shift=10/3

Shift=3.33cm.

Therefore, it appears to be raised by 3.33 cm.

Answer 2

Shift=realdepth∗(1−1/r.i.)

Shift=10∗(1−1/1.5)

Shift=10∗[(1.5−1]/1.5)

Shift=10∗(0.5/1.5)

Shift=10∗(1/3)

Shift=10/3

Shift=3.33cm.

Therefore,

it appears to be raised by 3.33 cm.

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