Physics, asked by rawataman2004, 9 months ago

when gravitational force is not responsible for free falling​

Answers

Answered by rishitakurasala
0

The free falling body  was considered by Einstein the reason for his "happiest thought" which paved the way to his Equivalence Priniciple.

In GR the model for a free falling body is given by the geodesic motion, if the tidal effect can be considered negligible.

For radial motion the 3 acceleration according to GR is given by

A=(1- 3*v2/c2- (4-2a)phi/c2) grad(phi)

where

a=1 for Schw coordinates

A1= (1- 3*v2/c2- 2phi/c2) grad(phi)

a=2 for Painlevè coordinates

A2=(1- 3*v2/c2) grad(phi)

a=0 for harmonic coordinates

A3=(1- 3*v2/c2- 4phi/c2) grad(phi)

In the  Field gravitation Theory with the Poincarè force,  the coordinates are relevant to the center of gravitation, though it gives the same result as the harmonic coordinates of GR.

If an object is close to the speed of light it is slowed down if it overcomes the

v= c /sqrt 3 in the three cases.

Answered by diyabhardwaj15
0

Answer:

In space there is no gravitational force on free falling bodies.

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