Question

when h²=ab the angle between pair of straight lines ax²+2hxy+by²=0 is (option a)π/2 b)π/4 c)π/6 d)0​

Answer 1

Required Answer:

• 0 (d)

Explanation:

The angle between 2 lines is calculated as:

$\\\quad\bullet\quad\sf \tan\theta= \dfrac{2\sqrt{h^{2} -ab} }{a+b}$

it is given that,

• h² = ab

⇒ h² - ab = 0

after substituting the value of (h²-ab), we'll get:-

$\\\quad\bullet\quad\boxed{\sf \tan\theta = 0 }$

hence, ∅ = 0

Explore More:

• h²-ab > 0 (two different and real lines)
• h²-ab = 0 (coinciding or parallel lines for non-homogenous lines and coinciding lines for homogenous lines as they pa.ss through the origin)
• h²-ab < 0 (two imaginary lines)

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Answer 2

Answer:

d) 0

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