Question

When H2O2 is treated with a solution of titanium dioxide in conc. H2SO4 an orange coloured compound is formed. The oxidation number of the metal in that compound is​

Answer 1

Answer:

Ti

+

+H

2

O

2

+2H

2

O→H

2

TiO

4

+4H

+

(Peritianic acid)

(orange)

Answer 2

When $H_2O_2$ is treated with a solution of titanium dioxide in presence of conc. $H_2SO_4$, Pertitanic acid is formed in which Ti has an oxidation number of +4.

• When $H_2O_2$ reacts with $TiO_2$ (titanium oxide) it gives $H_2TiO_4$ (Pertitanic acid). This compound is orange in color.
• We can easily find the oxidation number of the compound by looking at the structure of the acid.
• In this acid, 2 OH are bonded to Ti, and also an O-O (peroxide) is boned with Ti. So, if we let the oxidation number of Ti be x

        x + 2(-1) + 2 (-2) + 2 (+1) = 0

     ⇒ x = +4

Hence, we can conclude that the oxidation number of the metal of the compound is +4.

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