Question

when H2S is passed through dilute K2Cr2O7 milkiness appears

Answer 1

milkness in the in the solution is due to element S in solution . But the green colour appears because of CrCl3 in solution

Answer 2

When $H_2S$ is passed through dilute $K_2Cr_2O_7$ milkiness appears due to formation of elements sulfur.

Explanation:

• The reactants involved in the reaction are:

1. $H_2S$
2. $K_2Cr_2O_7$
3. HCl

• The products formed are as follows:

1. $CrCl_3$
2. $H_2O$
3. S
4. KCl

• The chemical equation involved in the reaction is as follows

$3H_2S+8HCl+K_2Cr_2O_7\rightarrow 2CrCl_3+7H_2O+3S+KCl$

• Due to the formation of element sulfur in the reaction, milkiness appears.
• The product formed is green in colour due to formation of $CrCl_3$.

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